Con los datos del ejercicio anterior. Si el primer barco
sufre una avería en sus motores cuando llevaba 6 horas de recorrido .
| Datos: |
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| A= |
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X1=v1t |
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SenB=6,55 |
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| B= |
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X1=(25/h)(6h) |
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Sen-¹(0,55)B |
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| C=101° |
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X1=150Km |
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B=√30° |
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| a=192Km |
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X2=v2t |
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B=33,3° |
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| b=150Km |
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X2=(32Km/h)(6h) |
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| c= |
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X2=192Km |
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| C^2=(192Km)^2+(150Km)-2(192Km)(150Km)cos101° |
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b/Senb=c/Senc |
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| C^2=36864Km^2-57600Km^2cos101° |
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150Km/Senb=265,25Km/Sen,101° |
| C^2=36864Km^2+22500Km^2-(-109900,598Km^2) |
C^2=a+b^2-2abcosc |
150Km.Sen101°=265,25Km.Senb |
| C^2=36864Km^2+22500Km^2-109900,598Km^2 |
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150Km.Sen101°=265,25Km.Senb |
| C^2=70354,598Km^2 |
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150Km.Sen101°/265,25Km=Senb |
| √C^2=√70354,598Km^2 |
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| C=268,25Km |
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